Aim: To arrange
several metal redox couples according to their standard reduction potential |
A half-reaction equation
represents a substance in equilibrium with an oxidised or reduced form of the same
substance. According to IUPAC recommendations a halfreaction equation is always written in
the form of a reduction with a substance on the left of the equation and a reduced form of
the substance on the right of the equation. For example:
By
reduced form of a substance is meant a species in which an element is
characterised by a lower oxidation state than in the oxidised containing
the same element.
For a strip of copper in equilibrium with a solution of copper(II) ions
the half-reaction equation is:
Examples of half-reaction equations for a dissolved gas in equilibrium with its ions are:
These so-called redox couples have an ability spontaneously to donate
or accept electrons from another substance depending on their potentiality
for so doing.
The potentiality of a particular redox couple to donate or accept electrons
from another redox couple can be qualitatively established by observing
the effects of bringing different redox couples together in a redox reaction.
Let us consider
the Zn2+/Zn, Pb2+/Pb and Cu2+/Cu redox
couples. Illustration R5 shows three simple redox reactions. In the first
a zinc rod in an aqueous solution of Pb(NO3)2 (lead(II)
nitrate) reduces the lead(II) ions to lead, the oxidation number of lead
changing from +II to 0. This is observed as a lead tree of
dendritic lead crystals. |
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At the same time zinc is oxidised to zinc(II) ions, the oxidation number
of zinc changing from 0 to +II.
Adding these two
half-reaction equations (top: right side; bottom : left side) so that no electrons are
left, gives the overall redox reaction equation:
We can therefore conclude
that the Zn2+/Zn half-reaction equation is more strongly reducing than the Pb2+/Pb
half-reaction equation.
In the second experiment a lead rod reduces copper(II) ions to copper metal, the oxidation
number of copper changing from +II to 0. The blue colour of the aqueous solution is seen
to disappear. At the same time the lead is itself oxidised to lead(II) ions, the oxidation
number of lead changing from 0 to +II. The lead rod becomes brown in colour as copper is
deposited on it.
Adding the two
half-reaction equations gives the overall redox reaction equation:
This shows that the lead
half-reaction equation is more strongly reducing than the copper half-reaction equation.
In the third experiment the zinc rod reduces the copper(II) ions to copper metal, the
oxidation number of copper changing from + II to 0, resulting in the original blue
solution becoming colourless and a red-brown deposit of copper being formed on the zinc
rod. At the same time the zinc is itself oxidised to zinc(II) ions, the oxidation number
of zinc changing from 0 to +II.
Adding the two
half-reaction equations gives the overall redox reaction equation.
We can therefore
conclude that the Zn2+/Zn half-reaction is more reducing than
the Pb2+/Pb half-reaction, which in turn is more reducing than
the Cu2+/Cu halfreaction equation.
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